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SOLVING
A SYSTEM OF EQUATIONS WITH THREE UNKNOWNS |
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Step 2: Eliminate x
again.
This time using Equation 2 (E2) and Equation 3 (E3) as
shown:
(E2) |
x + 3y + 7z = 1 → |
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-2(x + 3y + 7z = 1) → |
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-2x - 6y – 14z = -2 |
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(E3) |
2x + 9y + z = 8 |
-2x – 6y – 14z = -2
2x + 9y + z = 8
3y – 13z
= 6 (new Equation 5)
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