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| SOLVING
A SYSTEM OF EQUATIONS WITH THREE UNKNOWNS |
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Checking your answer:
| (E1) |
x + 4y – 2z = 3 → |
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-5 + 4(2) – 2(0) = -5 + 8 = 3 |
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| (E2) |
x + 3y + 7z = 1 → |
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-5 +3(2) +7(0) = -5 + 6 = 1 |
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| (E3) |
2x + 9y + z = 8 → |
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2(-5) + 9(2) + 0 = -10 + 18 = 8 |
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