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| SOLVING
A SYSTEM OF EQUATIONS WITH TWO UNKNOWNS |
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Now that we have solved for
x (x = y – 1), substitute the value for x in equation (1).
Substitute (y – 1) for x in equation 1:
- 2(y – 1) + 3y = 18
- 2y – 2 + 3y = 18
- 5y – 2 + 2 = 18 + 2
- 5y = 20
- 5y = 20
5 5
- y = 4
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